(a) Calculate the number of moles and the number of molecules present in 1.4 g of ethylene gas. What is the volume occupied by the same amount of ethylene?
(b) What is the vapour density of ethylene?
(a) The molecular weight of ethylene
= 12+2+12+2 =28g
Mole=given massmolar mass=1.428=0.05moles
Number of molecules in 1 mole = 6.023×1023
Therefore,
Number of molecules in 0.05 mole = 6.023×1023×0.05=0.3×10233×1022 molecules.
Volume of occupied by 1 mole = 22.4l
volume of occupied by 0.05 = 22.4 × 0.05 = 1.12 litre
(b)