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Question

A calorimeter contains 0.2kg of water at 30C. 0.1 kg of water at 60C is added to it, the mixture is well stirred
and the resulting temperature is found to be 35C. The thermal capacity of the calorimeter is

A
6300 J/K
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B
1260 J/K
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C
4200 J/K
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D
None of these
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Solution

The correct option is B 1260 J/K
Let X be the thermal capacity of calorimeter and specific heat of water = 4200 J/kg-K Heat lost by 0.1 kg of water = Heat gained by water in calorimeter + Heat gained by calorimeter
0.1×4200×(6035)=0.2×4200×(3530)+X(3530)10500=4200+5XX=1260 J/K

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