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A calorimeter...

Question

A calorimeter contains $50 g$ of water at $50^{o} C$ . The temperature falls to $46^{o} C$ in $10$ minutes. When the calorimeter contains $100 g$ of water at $50^{o} C$ , it takes $18$ minutes for the temperature to fall to $46^{o} C$ . The water equivalent of the calorimeter (in g) is . Find the value of $n$ .

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Solution

$\frac{50 + w}{10} = \frac{100 + w}{18}$
$w = 12.5 g$

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A calorimeter contains 50 g of water at 50^0 C. The temperature falls to $45^{0}$ C in 10 minutes. When the calorimeter contains 100 g of water at $50^{0}$ C, it takes 18 minutes for the temperature to become $45^{0}$ C. Find the water equivalent of the calorimeter.

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