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Question

A calorimeter of water equivalent 15g contains 165g of water at 25C. Steam at 100C is passed through the water for some time. The temperature is increased to 30C and the mass of the calorimeter and its contents is increased by 1.5 g. Calculate the latent heat of vaporization of water. Heat capacity of water is 1 cal/gC


A
630 cal/g
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B
530 cal/g
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C
1530 cal/g
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D
1500 cal/g
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Solution

The correct option is B 530 cal/g

Let L be the specific latent heat of vaporization of water.

The mass of the steam condensed is 1.5g.

Heat lost in condensation of steam is­ Q1=(1.5g)L
The condensed water cools from 100C to 30C.

Heat lost in this process is = Q2=(1.5g)(1 cal/gC)(70C)=105 cal
Heat supplied to the calorimeter and to the cold water = Q3=(15g+165g)(1 cal/gC)(5C)=900 cal
If no heat is lost to the surrounding,

Q1+Q2 = Q3
(1.5)L+105=900
L=530 cal/g


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