A can complete a piece of work in the same amount of time as B and C together take to complete the same work. A and B together can complete that work in 10 days and C alone can complete it in 50 days.
How many days will it take for B to complete the work alone?

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Solution

The correct option is C
25

Work done by C in one day = $\frac{1}{50}$

Work done by B in one day = $\frac{1}{x}$

Work done by A in one day = $\frac{1}{50} + \frac{1}{x}$

$\frac{1}{50} + \frac{2}{x} = \frac{1}{10}$

$x = 25$ days

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A can complete a piece of work in the same amount of time as B and C together take to complete the same work. A and B together can complete that work in 10 days and C alone can complete it in 50 days. How many days will it take for B to complete the work alone?

The correct option is C 25 Work done by C in one day = 150 Work done by B in one day = 1x Work done by A in one day =150+1x 150+2x=110 x=25 days

A can complete a piece of work in the same amount of time as B and C together take to complete the same work. A and B together can complete that work in 10 days and C alone can complete it in 50 days.
How many days will it take for B to complete the work alone?

The correct option is C
25

Work done by C in one day = $\frac{1}{50}$

Work done by B in one day = $\frac{1}{x}$

Work done by A in one day = $\frac{1}{50} + \frac{1}{x}$

$\frac{1}{50} + \frac{2}{x} = \frac{1}{10}$

$x = 25$ days