A can complete a work in 6 days. But due to other work, his efficiency was reduced by 50%, so he took B's help and completed the work in 6 days. If B alone was assigned the task, how many days does he take to complete the work?

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Solution

The correct option is E
12

Time taken by A to complete the work = 6 days

Work done by A in a day when he is 50% efficient = $\frac{1}{12}$

Let the work done by B in a day = $\frac{1}{x}$

$\frac{1}{12} +$ $\frac{1}{x} =$ $\frac{1}{6}$

$x = 12 d a y s$

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A can complete a work in 6 days. But due to other work, his efficiency was reduced by 50%, so he took B's help and completed the work in 6 days. If B alone was assigned the task, how many days does he take to complete the work?

The correct option is E 12 Time taken by A to complete the work = 6 days Work done by A in a day when he is 50% efficient =112 Let the work done by B in a day = 1x 112+1x=16 x=12days

The correct option is E
12

Time taken by A to complete the work = 6 days

Work done by A in a day when he is 50% efficient = $\frac{1}{12}$

Let the work done by B in a day = $\frac{1}{x}$

$\frac{1}{12} +$ $\frac{1}{x} =$ $\frac{1}{6}$

$x = 12 d a y s$