A can do a piece of work in 20 days whereas A and B can do the same in 4 days. If A has (x+10)% efficiency of B, then find x.

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Solution

The correct option is B
15

Work done by A in one day = $\frac{1}{20}$

Let the time taken by B to complete the work be x days

$\frac{1}{20} +$ $\frac{1}{x} =$ $\frac{1}{4}$

x = 5

So, A has 25% efficiency of B.

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A can do a piece of work in 20 days whereas A and B can do the same in 4 days. If A has (x+10)% efficiency of B, then find x.

The correct option is B 15 Work done by A in one day = 120 Let the time taken by B to complete the work be x days 120+1x=14 x = 5 So, A has 25% efficiency of B.

The correct option is B
15

Work done by A in one day = $\frac{1}{20}$

Let the time taken by B to complete the work be x days

$\frac{1}{20} +$ $\frac{1}{x} =$ $\frac{1}{4}$

x = 5

So, A has 25% efficiency of B.