Question

A can do a piece of work in $9$ days. B is $50\%$ more efficient than A. The number of days it takes B to do the same piece of work is:

• A. $13\frac{1}{2}$
• B. $4\frac{1}{2}$
• C. $6$
• D. $3$

Answer 1

Answer: (C)

$6$

In one day A can do $1/9$ of the job.

Since B is $50\%$ more efficient than A

B can do $\frac{3}{2}.\frac{1}{9}=\frac{1}{6}$ of the job in one day.

Therefore, B needs $6$ days for the complete job.