Question

$A$ can do a work in $9$ days. If $B$ is $50$% more efficient than $A$, then in how many days can $B$ do the same work?

• A. $13.5$
• B. $4.5$
• C. $6$
• D. $5$

Answer 1

The correct option is C $6$

Let total work to be done=1

Then, A's one day work= (total work) / (total days taken by A) $=1/9$

B's one day work= 150% of A's one day work (because B is 50% more efficient)

=(1/9)*(150/100)=1/6

Total time taken by B to do total work= $\frac{1}{\left(1/6\right)}=6$