A can finish a task in 18 days and B can complete the same task in 15 days. B worked for 10 days and left the job.
How many days will A take to finish the remaining task when working alone?

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Solution

The correct option is C
6

B’s 10 days work $= (\frac{1}{15} \times 10) = \frac{2}{3}$

Remaining work $= (1 - \frac{2}{3}) = \frac{1}{3}$

Now, $\frac{1}{18}$ work is done by A in 1 day.

∴ $\frac{1}{3}$ of work is done by A in $18 \times \frac{1}{3} = 6 d a y s$

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A can finish a task in 18 days and B can complete the same task in 15 days. B worked for 10 days and left the job. How many days will A take to finish the remaining task when working alone?

The correct option is C 6 B’s 10 days work =(115×10)=23 Remaining work =(1−23)=13 Now, 118 work is done by A in 1 day. ∴ 13 of work is done by A in 18×13=6 days

A can finish a task in 18 days and B can complete the same task in 15 days. B worked for 10 days and left the job.
How many days will A take to finish the remaining task when working alone?

The correct option is C
6

B’s 10 days work $= (\frac{1}{15} \times 10) = \frac{2}{3}$

Remaining work $= (1 - \frac{2}{3}) = \frac{1}{3}$

Now, $\frac{1}{18}$ work is done by A in 1 day.

∴ $\frac{1}{3}$ of work is done by A in $18 \times \frac{1}{3} = 6 d a y s$