A can finish a work in 18 days and B can do the same work in half the time taken by A. Then, working together, what part of the same work can they finish in a day?

1/6

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1/9

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2/5

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2/7

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1/5

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Solution

The correct option is A
1/6

A’s 1 day’s work = $\frac{1}{18}$ and B’s 1 day’s work = $\frac{1}{9}$

$∴$ (A+B)’s 1 day’s work = $(\frac{1}{18} + \frac{1}{9}) = \frac{1}{6}$

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A can finish a work in 18 days and B can do the same work in half the time taken by A. Then, working together, what part of the same work can they finish in a day?

The correct option is A 1/6 A’s 1 day’s work = 118 and B’s 1 day’s work = 19 ∴ (A+B)’s 1 day’s work = (118 + 19) = 16

The correct option is A
1/6

A’s 1 day’s work = $\frac{1}{18}$ and B’s 1 day’s work = $\frac{1}{9}$

$∴$ (A+B)’s 1 day’s work = $(\frac{1}{18} + \frac{1}{9}) = \frac{1}{6}$