Question

$A$ can hit a target $3$ times in $6$ shots; $B,2$ times in $4$ shots and $C,4$ times in $4$ shots. All of them fire at a target independently. The probability that the target will be hit is

• A. $1$
• B. $0.5$
• C. $0.25$
• D. $0.125$

Answer 1

The correct option is A $1$

$P\left(A\right)=\frac{3}{6},P\left(B\right)=\frac{2}{4},P\left(C\right)=1$
$P(A\cup B\cup C)=1-P\left(\overline{A}\right)\cdot P\left(\overline{B}\right)\cdot P\left(\overline{C}\right)=1-0=1$