Question

A can hit a target 4 times on 5 shots B can hit 3 times on 4 shots and C can hit 2 on 3 shots , wats the probability tat all may hit

Answer 1

$$\begin{gathered} \mathrm{Let}\mathrm{A}\mathrm{be}\mathrm{the}\mathrm{event}\mathrm{that}\mathrm{A}\mathrm{hits}\mathrm{the}\mathrm{target}. \\ \mathrm{Let}\mathrm{B}\mathrm{be}\mathrm{the}\mathrm{event}\mathrm{that}\mathrm{B}\mathrm{hits}\mathrm{the}\mathrm{target}. \\ \mathrm{Let}\mathrm{C}\mathrm{be}\mathrm{the}\mathrm{vent}\mathrm{that}\mathrm{C}\mathrm{hits}\mathrm{the}\mathrm{target} \\ \mathrm{Now},\mathrm{P}\left(\mathrm{A}\right)=\frac{4}{5};\mathrm{P}\left(\mathrm{B}\right)=\frac{3}{4};\mathrm{P}\left(\mathrm{C}\right)=\frac{2}{3} \\ \mathrm{P}\left(\mathrm{all}\mathrm{may}\mathrm{hit}\mathrm{the}\mathrm{target}\right)=\mathrm{P}\left(\mathrm{A}\right).\mathrm{P}\left(\mathrm{B}\right).\mathrm{P}\left(\mathrm{C}\right) \\ =\frac{4}{5}\times \frac{3}{4}\times \frac{2}{3} \\ =\frac{2}{5} \end{gathered}$$