A can lay railway track between two given stations in 16 days and B can do the same job in 12 days. With help of C, they did the job in 4 days only. Then, C alone can do the job in:

9 \frac{1}{5}

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9 \frac{3}{5}

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9 \frac{2}{5}

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Solution

The correct option is B $9 \frac{3}{5}$

(A + B + C)'s 1 day's work = $\frac{1}{4}$

A's 1 day's work = $\frac{1}{16}$

B's 1 day's work = $\frac{1}{12}$

C's 1 day's work =

$\frac{1}{4} - \frac{1}{16} - \frac{1}{12} = \frac{5}{48}$

So, C alone can do the work in

= $\frac{48}{5} = 9 \frac{3}{5}$ days

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A can do a job in 16 days and B can do the same job in 12 days. With the help of C, they can finish the job in 6 days only. Then, C alone can finish it in

(a) 34 days

(b) 22 days

(d) 48 days

Q. Tick (✓) the correct answer:
A can do a job in 16 days and B can do the same job in 12 days. With the help of C, they can finish the job in 6 days only. Then, C alone can finish it in
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(b) 22 days
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A can lay a railway track between two given stations in $16$ days and B can do the same job in $12$ days. With help of C, they did the job in $4$ days only. How many days will C take to do the job alone?

A can laid railway track between two given stations in 16 days and B can do the same job in 12 days. With help of C, they did the job in 4 days only. How many days will C complete the work alone?