Question

A candidate who gets $20$% marks in an examination fails by $30$ marks but another candidate who gets $32$% gets $42$ marks more than the pass mark. Then, the percentage of pass mark is

• A. $52$
• B. $50$
• C. $33$
• D. $25$

Answer 1

Answer: (D)

$25$

Let the total marks be $x$.
According to the question,
$\frac{20}{100}\times x+30=\frac{32}{100}\times x-42$
$42+30=\frac{32}{100}x-\frac{20}{100}x$
$72\times 100=12x\Rightarrow x=600$
Passing marks $=\frac{20}{100}x+30=\frac{20}{100}\times 600+30=150$
Required percentage $=\frac{150}{600}\times 100=25$%.