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Question

A capacitance of 2 μF is required in an electrical circuit across a potential difference of 1.0 kV. A large number of 1 μF capacitors are available which can withstand a potential difference of not more than 300V. The minimum number of capacitors required to achieve this is

A
32
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B
2
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C
16
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D
24
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Solution

The correct option is A 32
To hold 1kV potential difference minimum four capacitors are required in series C=1/4(for 4 capacitors).

For overall capacitance of 2 μF, 8 such branches are needed.
Or, equivalent is Ceq=8×0.25=2 μF

Total capacitors required = 8×4=32


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