Question

A capacitor 1mF withstands a maximum voltage of 6KV, while another capacitor 2mF withstands a maximum voltage of 4KV. If the capacitors are connected in series, the system will withstand a maximum voltage of?

• A. 2 KV
• B. 4 KV
• C. 6 KV
• D. 9 KV

Answer 1

The correct option is D 9 KV

$q_1=C_1{V}_1={10}^{-3}\times 6\times {10}^3=6C$
$q_1=C_2{V}_2=2\times {10}^{-3}\times 4\times {10}^3=8C$
$Q=q_1=6CQ=CV$
$6=\left(\frac{C_1{C}_2}{C_1+C_2}\right)V$
$6=\frac{2}{3}\times {10}^{-3}V$
$V=9\times {10}^{3}V$
$=9KV$