A capacitor 4μF charged to 50V is connected to another capacitor of 2μF charged to 100V with plates of like charges connected together. The total energy before and after connection in multiples of (10−2J) is
A
1.5 and 1.33
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B
1.33 and 1.5
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C
3.0 and 2.67
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D
2.67 and 3.0
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Solution
The correct option is A1.5 and 1.33 The total energy before connection 12×4×10−6×(50)2+12×2×10−6×(100)2 =1.5×10−2J
When connected in parallel 4×50+2×100=6×V⇒V=2003
Total energy after connection =12×6×10−6×(2003)2=1.33×10−2J