Question

A capacitor has a capacitance of $7.28\mu F$. What amount of charge in ($\mu C$) must be placed on the plates to make the potential difference between its plates equal to 25.0 V?

Answer 1

We know that charge on capacitor is $Q=CV=7.28\times 25=182\mu C$

The charges on each plate of capacitor are equal and opposite. One plate will get charge $-Q$ and the other plate is $+Q$.