Question

A capacitor having capacity of $2.0\mu F$ is charged to $200V$ and then the plates of the capacitors are connected to a resistance wire. The heat produced in joule will be :

• A. $2\times {10}^{-2}$
• B. $4\times {10}^{-2}$
• C. $4\times {10}^4$
• D. $4\times {10}^{10}$

Answer 1

The correct option is B $4\times {10}^{-2}$

Heat produce in a wire is equal to energy stored in capacitor.
$H=\frac{1}{2}C{V}^2$
$=\frac{1}{2}\times (2\times {10}^{-6})\times (200{)}^2$
$={10}^{-6}\times 200\times 200$
$=4\times {10}^{-2}J$.