Question

A capacitor is charged to a certain potential difference and stores some energy. In order to double the energy stored in the capacitor, the potential difference must be increased nearly by

• A. $100\%$
• B. $41\%$
• C. $50\%$
• D. $29\%$

Answer 1

The correct option is B

$41\%$

$U=\frac{C{V}^2}{2}\Rightarrow V=\sqrt{\frac{2U}{C}}$ .Hence, to double U, V must become $\sqrt{2}$ times, which is 1.414 times i.e., 41%