Question

A capacitor is charged with a battery and energy stored is $U$. After disconnecting battery another capacitor is of same capacity is connected in parallel with it. Then energy stored in each capacitor is:

• A. $U/2$
• B. $U/4$
• C. $4U$
• D. $2U$

Answer 1

The correct option is B $U/4$

Now charge will flow in such a way that total charge is $Q$ and potential $\frac{d}{f}$ across both capacitors remains same.

$V=\frac{Q}{2C}$

Energy in each capacitor $=\frac{1}{2}C{V}^2=\frac{1}{2}C(\frac{Q}{2C}{)}^2=\frac{1}{4}(\frac{1}{2}.(\frac{Q^2}{2C}{)}^{)}=\frac{U}{4}$