wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A capacitor made of two parallel places each of plate area A and separations d, being charged by an external ac source. How the displacement current inside the capacitor is same as the current charging the capacitor

Open in App
Solution


TD=ε0dμEdtlet the altering emf charging the plates of capacitor be E=E0sinωt
charge on the capacitor q=EC=CE0sinωt
I=dqdt=ddt(CE0sinωt)=ωCE0cosωt=I0cosωt(whereI0=ωCE0)
Displacement current
ID=ε0dψEdt=ε0AdEdt=ε0Ad(qε0A)dt=ε0Addt(CE0sinωtε0A)
=ddt(CE0sinωt)=ωCE0cosωt=I0cosωt
Thus the displacement current inside the capacitor is the same as current charging the capacitor.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Parallel Plate Capacitor
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon