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Question

A capacitor made of two parallel places each of plate area A and separations d, being charged by an external ac source. How the displacement current inside the capacitor is same as the current charging the capacitor

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Solution


TD=ε0dμEdtlet the altering emf charging the plates of capacitor be E=E0sinωt
charge on the capacitor q=EC=CE0sinωt
I=dqdt=ddt(CE0sinωt)=ωCE0cosωt=I0cosωt(whereI0=ωCE0)
Displacement current
ID=ε0dψEdt=ε0AdEdt=ε0Ad(qε0A)dt=ε0Addt(CE0sinωtε0A)
=ddt(CE0sinωt)=ωCE0cosωt=I0cosωt
Thus the displacement current inside the capacitor is the same as current charging the capacitor.

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