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Question

A capacitor of 10μF charged upto 250 V is connected in parallel with another capacitor of 5μF charged upto 100 V. The common potential is :

A
200 V
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B
300 V
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C
400 V
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D
500 V
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Solution

The correct option is A 200 V
The equivalent capacitance of the capacitors joined in parallel is equal to the sum of their individual capacitances.
Let the charge on the capacitors be q1 and q2. Then total charge
Q=Q+Q2
CV=C1V1+C2V2
Since, capacitors are connected in parallel equivalent capacitance is C=C1+C2
V=C1V1+C2V2C1+C2
Given, C1=10μF,V1250V,C2=5μF,V2=100V
V=(10×106×250)+(5×106×100)(10×106+5×106)
V=3000×10615×106=200V

706344_642460_ans_b0b1131ddb494444926dafb9ec4449ce.jpg

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