A capacitor of 20μF charged to 500V, is connected in parallel to another capacitor of 10μF charged to 200V, Find the common potential?
A
200V
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B
400V
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C
600V
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D
800V
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Solution
The correct option is B400V The common potential Vcommon=C1V1+C2V2C1+C2 Here C1=20μF=20×10−6F,V1=500V C2=10μF=10×10−6F,V2=200V ⇒Vcommon=20×10−6×500+10×10−6×20020×10−6+10×10−6 ⇒Vcommon=400V