Question

A capacitor of $20\mu F$ is connected in series with a $25\Omega$ resistance to a peak e.m.f $240v$, $50Hz$ A.c. Calculate
(i)the capacitive reactance of the circuit.
(ii)an impedance of the circuit

Answer 1

(i)

Capacitive reactance of the circuit $=\frac{1}{2\pi fC}$

$=\frac{1}{2\times 3.14\times 50\times 20\times {10}^{-6}}=159\Omega$

(ii)

Impedance of the circuit $=25+159\approx 184\Omega$