A capacitor of $8 μ f$ is charged to a potential of $1000 V$ . The energy stored in the capacitor is :

8 J

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12 J

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2 J

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4 J

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Solution

The correct option is D $4 J$
We know,
$E = \frac{1}{2} C V^{2}$
$E = \frac{1}{2} (8 \times 10^{- 6}) (10^{3})^{2}$
$E = 4 J$

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A capacitor of 8μf is charged to a potential of 1000V. The energy stored in the capacitor is :

The correct option is D 4JWe know,E=12CV2E=12(8×10−6)(103)2E=4J

A capacitor of $8 μ f$ is charged to a potential of $1000 V$ . The energy stored in the capacitor is :

The correct option is D $4 J$
We know,
$E = \frac{1}{2} C V^{2}$
$E = \frac{1}{2} (8 \times 10^{- 6}) (10^{3})^{2}$
$E = 4 J$