Question

A capacitor of capacitance $0.1\mu F$ is connected to a battery of emf 8 V (as shown in Figure) under the steady-state condition.

Answer 1

The equivalent circuit is shown in Figure. (b).
The current through $R_{1}is8/20=0.4A$
In the steady state, the potential difference across $AB$ is 4 V.
Charge on capacitor in steady state is $q=CV=0.4\mu C$.
Current through resistor $R$ is $I=\frac{V}{R}=\frac{4}{20}=0.2A$