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Capacitance of a Random Conductor

A capacitor o...

Question

A capacitor of capacitance $10, f$ is charged to a potential of 100 $V$ Now connecting it in parallel with an uncharged capacitor, the resultant potential difference becomes 40 volt.The capacitance of this capacitor is

A

2.5, F

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B

5, F

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C

10, F

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D

15, F

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Solution

The correct option is D $15, F$
$\begin{matrix} Q = 10 \times 100 V = 1000 C (x - 0) 10 + (x - 0) C = 1000 \Rightarrow 400 + 40 C = 1000 40 C = 600 C = 15 F H e n c e, o p t i o n D i s c o r r e c t a n s w e r . \end{matrix}$

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