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Question

A capacitor of capacitance 1neu F is charged by connecting a battery of negligible internal resistance and EMF 10V across it. Calculate the amount of charge supplied by the battery in charging the capacitor fully?

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Solution

Dear student,
since we know
q= C x V where q is the charge in the capacitor and C is the capacitance and V is the voltage across the capacitor.
So here q = 10^-9 F x 10 V
= 10^-8 = 0.01 micro C charge is supplied by the battery.
regards

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