Question

A capacitor of capacitance $50pF$ is charged by $100V$ source. It is then connected to another uncharged identical capacitor. Electrostatic energy loss in the process is ________ $nJ.$

Answer 1

Electrical energy lost $=\frac{1}{2}\left(\frac{1}{2}C{V}^2\right)$

$=\frac{1}{2}\times \frac{1}{2}\times 50\times {10}^{-12}\times (100{)}^2$

$=\frac{500}{4}nJ$
$=125nJ$