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Question

A capacitor of capacitance C1=1.0μF withstand a maximum voltage E1=6.0 kV while a capacitor of capacitance C2=2.0μF can withstand the maximum voltage E2=4.0 kV. For what voltage will the system of these two capacitors with stand , if they both are connected in series ?

A
9 kV
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B
10 kV
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C
11 kV
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D
12 kV
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Solution

The correct option is A 9 kV
q1=C1E1=1×106×6×103=6000μC

q2=C2E2=2×106×4×103=8000μC

The maximum charge should be equal to the the smaller one in series connection.


In series combination , Cs=C1C2C1+C2
Cs=1×21+2=23 μF ; qmax=6000 μC

The maximum voltage , Emax=qmaxCs=6000×106(23)×106

Emax=9000 V or 9 kV

Hence, option (a) is the correct answer.

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