Question

A capacitor of capacitance C = 4 $\mu F$ is connected as shown in figure. If internal resistance of the cell is 0.5 . The charge on the capacitor plates is

• A. zero
• B. 8 $\mu C$
• C. 4 $\mu C$
• D. 6 $\mu C$

Answer 1

The correct option is B 8 $\mu C$

At steady state the capacitor is open circuited so no current flows through the $10$ $ohm$ resistor$.$

Current flowing through $2$ $ohm$ resistor is

$i=\frac{2.5}{2+0.5}=2A$

Voltage across capacitor terminal$:$ $2.5-0.5\times 1=2V$

Charge in capacitor plates $4\times {10}^{-6}\times 2=8\mu C$

Hence,

option $\left(B\right)$ is correct answer.