Question

A capacitor of capacitance C is charged to a potential V. The flux of the electric field through a closed surface enclosing the capacitor is
(a) $\frac{CV}{{\epsilon }_0}$

(b) $\frac{2CV}{{\epsilon }_0}$

(c) $\frac{CV}{2{\epsilon }_0}$

(d) zero.

Answer 1

(d) zero



Since the net charge enclosed by the Gaussian surface is zero, the total flux of the electric field through the closed Gaussian surface enclosing the capacitor is zero.

$\Phi =∯E.ds=\frac{q}{{\in }_0}$= 0
Here,
$\Phi$ = Electric flux
q = Total charge enclosed by the Gaussian surface.