A capacitor of capacitance C- is connected across an AC source of voltage V- given by V - V0sin- t- The displacement current between the plates of the capacitor- would then be given by

Given V = V_0sinω t ...(1) Now, displacement current i_d is given by, I_d = C dVdt= C ddt (V_0 sinω t) nbsp; = C (V_0 ω) cosω t =V_0ω Ccosω t Hence ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard IX

Physics

Electric Field

A capacitor o...

Question

A capacitor of capacitance $C,$ is connected across an AC source of voltage $V,$ given by $V = V_{0} sin ω t$ . The displacement current between the plates of the capacitor, would then be given by

I_{d} = V_{0} ω C sin ω t

No worries! We‘ve got your back. Try BYJU‘S free classes today!

I_{d} = V_{0} ω C cos ω t

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

I_{d} = \frac{V_{0}}{ω C} cos ω t

No worries! We‘ve got your back. Try BYJU‘S free classes today!

I_{d} = \frac{V_{0}}{ω C} sin ω t

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
$I_{d} = V_{0} ω C cos ω t$
Given $V = V_{0} sin ω t . . . (1)$

Now, displacement current $i_{d}$ is given by,

$I_{d} = C \frac{d V}{d t} = C \frac{d}{d t} (V_{0} sin ω t)$

$= C (V_{0} ω) cos ω t$

$= V_{0} ω C cos ω t$

Hence, $(B)$ is the correct answer.

Suggest Corrections

Similar questions

Q. A parallel plate capacitor of capacitance

20 μ F

is being charged by a voltage source whose potential is changing at the rate of

3 V / s

. The conduction current through the connecting wires and the displacement current through the plates of the capacitor would be respectively

Q. A

20 V, 50 Hz

AC source is connected across a resistor of resistance

R

and a capacitor of capacitance

C

as shown in the figure. The voltage across the resistor is

12 V

. The voltage across the capacitor is

Q. The given figure represents the phasor diagram of a series

L C R

circuit connected to an

A C

source. At instant

t

when the source voltage is given by

V = V_{0} cos ω t

, the current in the circuit in terms of peak current

I_{0}

will be
Given:

V_{O R} = \sqrt{3} V

= Voltage Across Resistor

V_{O L} = 3 V

= Voltage Across Inductor

V_{O C} = 2 V

= Voltage Across capacitor

Q. An ac voltage source

V = V_{0} sin ω t

is connected across resistance

R

and capacitance

C

as shown in figure. It is given that

R = \frac{1}{ω C}

. The peak current is

I_{0}

. If the angular frequency of the voltage source is changed to

\frac{ω}{\sqrt{3}}

by keeping

R

and

C

fixed, then the new peak current in the circuit is-

Q. A parallel plate capacitor of capacitance

20 μ F

is being charged by a voltage source whose potential is changing at the rate of

3 V / s

. The conduction current through the connecting wires and the displacement current through the plates of the capacitor would be respectively

Join BYJU'S Learning Program

A capacitor of capacitance C, is connected across an AC source of voltage V, given by V=V0sinωt. The displacement current between the plates of the capacitor, would then be given by

The correct option is B Id=V0ωCcosω tGiven V=V0sinωt ...(1) Now, displacement current id is given by, Id=CdVdt=Cddt(V0sinωt) =C(V0ω)cosωt =V0ωCcosωt Hence, (B) is the correct answer.

A capacitor of capacitance $C,$ is connected across an AC source of voltage $V,$ given by $V = V_{0} sin ω t$ . The displacement current between the plates of the capacitor, would then be given by

The correct option is B
$I_{d} = V_{0} ω C cos ω t$
Given $V = V_{0} sin ω t . . . (1)$

Now, displacement current $i_{d}$ is given by,

$I_{d} = C \frac{d V}{d t} = C \frac{d}{d t} (V_{0} sin ω t)$

$= C (V_{0} ω) cos ω t$

$= V_{0} ω C cos ω t$

Hence, $(B)$ is the correct answer.