Question

A capacitor of capacity $10$ $\mu F$ is charged to a potential of $400$ $V$. When its both plates are connected by a conducting wire, then heat generated will be:

• A. $80$ $J$
• B. $0.8$ $J$
• C. $8\times {10}^3$ $J$
• D. $8\times {10}^{-6}$ $J$

Answer 1

The correct option is B $0.8$ $J$

$C=10$ $\mu F$

$V=400$ $V$

$E=\frac{1}{2}C{V}^2$

$⟹E=\frac{1}{2}\times 10\times {10}^{-6}\times 400\times 400$

$⟹E=\frac{16}{2}\times {10}^5\times {10}^{-6}$

$⟹E=0.8$ $J$