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Byju's Answer

Standard XII

Physics

Energy of a Capacitor

A capacitor o...

Question

A capacitor of capacity $6 μ F$ and initial charge $160 μ C$ is connected with a key $s$ and resistance as shown in figure. Point M is earthed. If key is closed at $t = 0$ ; then the current through resistances $R_{1}$ and $R_{2}$ at $t = 16 μ s$ are

i_{1} = \frac{10}{3 e}

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i_{1} = \frac{20}{3 e}

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i_{2} = \frac{20}{3 e}

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i_{2} = \frac{10}{3 e}

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Solution

The correct options are
A $i_{1} = \frac{10}{3 e}$
C $i_{2} = \frac{20}{3 e}$

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Similar questions

A capcacitor of capacity 6μF and intial charge 160μC is connected with a key S and different resistors as shown in figure. Point M is earthed. If key is closed at t = 0; then the current through resistance R (=1Ω) at 6 = 16μs is

Q. A capacitor of capacity

6 μ F

and initial charge

160 μ C

in connected with key S and resistance as shown in figure. Point

M

is earthed. If key is closed at

t = 0

, then the current through resistance

(R = 1 Ω

) at

(t = 16 μ s)

\frac{4 n}{3 e} A

, then find

n

Q. A capacitor of capacitance

6 μ F

and initial charge

192 μ C

is connected with a key

S

and resistance as shown in figure. Point

M

is earthed. If key is closed at

t = 0

, then the current (in Ampere) through resistance

R (1 Ω)

, at

t = 16 ln 2 μ s

Q. Key is closed at time

t = 0

i = i_{1}

t = 0

and

i = i_{2}

at time

t = \infty

\frac{i_{1}}{i_{2}}

equals

Q. In the circuit shown in the figure

C_{1} = 2 C_{2}

, switch

S

is closed at time

t = 0

. Let

i_{1}

and

i_{2}

be the currents flowing through

C_{1}

and

C_{2}

at any time

t

, then the ratio

i_{1} / i_{2}

(assume capacitors were initially uncharged.)

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A capacitor of capacity 6μF and initial charge 160μC is connected with a key s and resistance as shown in figure. Point M is earthed. If key is closed at t=0; then the current through resistances R1 and R2 at t=16μs are

The correct options are A i1=103e C i2=203e

A capacitor of capacity $6 μ F$ and initial charge $160 μ C$ is connected with a key $s$ and resistance as shown in figure. Point M is earthed. If key is closed at $t = 0$ ; then the current through resistances $R_{1}$ and $R_{2}$ at $t = 16 μ s$ are

The correct options are
A $i_{1} = \frac{10}{3 e}$
C $i_{2} = \frac{20}{3 e}$