A capacitor stores charge Q at a potential difference V. If the voltage applied by a battery to the capacitor is doubled to 2V, then

The capacitance falls to half its initial value and the charge remains the same

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The capacitance and the charge both fall to half their initial values

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The capacitance and the charge both double

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The capacitance remains the same and the charge doubles

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Solution

The correct option is D
The capacitance remains the same and the charge doubles

The capacitance for a given system is a constant and is independent of charge as well as potential. As $C = \frac{Q}{V}$ , when V doubles, Q doubles to keep C constant

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A capacitor stores charge Q at a potential difference V. If the voltage applied by a battery to the capacitor is doubled to 2V, then

The correct option is D The capacitance remains the same and the charge doubles The capacitance for a given system is a constant and is independent of charge as well as potential. As C=QV, when V doubles, Q doubles to keep C constant

The correct option is D
The capacitance remains the same and the charge doubles

The capacitance for a given system is a constant and is independent of charge as well as potential. As $C = \frac{Q}{V}$ , when V doubles, Q doubles to keep C constant