Question

A capillary tube of radius $0.20mm$ is dipped vertically in water. The height (in $cm$) of the water column raised in the tube, will be (surface tension of water $=0.075N/m$ and density of water $=1000kg/m^3$. Take $g=10m/s^2$ and contact angle $0^{\circ }$).

Answer 1

We have,

$h=\frac{2T\cos \theta }{r\rho g}$

Here, $T=0.075N/m$ and $r=0.20mm=0.2\times {10}^{-3}m,\rho =1000kg/m^3,\theta =0^{\circ },g=10m/s^2$

$h=\frac{2\times 0.075\times 1}{(0.20\times {10}^{-3})\times \left(1000\right)\left(10\right)}$

$h=0.075m=7.5cm$