A capillary tube of radius $0.25 m m$ is submerged vertically in water so that $25 m m$ of its length is outside water. The radius of curvature of the meniscus will be (S.T of water $= 75 \times 10^{- 3} N / m$ )

0.2 m m

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0.4 m m

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0.6 m m

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0.8 m m

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Solution

The correct option is C $0.6 m m$
$c o s θ = \frac{d e n s i t y \times g \times h \times r}{2 T}$
radius of curvature of meniscus = 0.6mm

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