A capillary tube of radius $0.25 m m$ is submerged vertically in water so that $25 m m$ of its length outside water. The radius of curvature of the meniscus will be $(T = 7.5 \times 10^{- 3} N / m)$ .

0.2 m m

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0.4 m m

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0.6 m m

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0.8 m m

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Solution

The correct option is C $0.6 m m$
$h = \frac{2 T}{d g x}$
$h = \frac{2 \times 7.5 \times 10^{-} 3}{1000 \times 10 \times d}$
$h = 25 m m$
$d = 0.6 m m$

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