Question

A capillary tube of radius 0.2mm is dipped vertically in water . Find the height of water column raised in the tube , if density of water= 1000kg/m3 , surface tension of water is 0.075 N/m, g=10m/s2.

Answer 1

$$\begin{gathered} DearStudent, \\ Given, \\ r=0.2mm=0.2\times {10}^{-3}m,\rho =1000kg/m^3,S=0.075N/m \\ Asthetubeisdippedvertically, \\ \theta =0^0 \\ Heightofthewatercolumnis, \\ h=\frac{2S\cos \theta }{r\rho g} \\ \Rightarrow \\ h=\frac{2\times 0.075\times \cos 0}{0.2\times {10}^{-3}\times 1000\times 10}=\frac{2\times 0.075}{2}=\mathbf{0}\mathbf{.}\mathbf{075}\mathit{m}\mathbf{=}\mathbf{7}\mathbf{.}\mathbf{5}\mathit{c}\mathit{m} \\ Regards. \end{gathered}$$