Question

A capillary tube of radius $r$ is immersed in a liquid. and mass if liquid, which rises p in it is $M$. If liquid radius of tube is doubled, then the mass of liquid which will rise in capillary tube will be

• A. $2M$
• B. $M$
• C. $M/2$
• D. $M/4$

Answer 1

The correct option is A $2M$

Mass of liquid which rises in the capillary,
$m=\left(\pi r^2\right)h\rho =\pi r^2\times \frac{2\sigma cos\theta }{r\rho g}\times \rho$
$\Rightarrow m\propto r$