Question

A car 2 m long and 3 m wide is moving at 13 m/s when a bullet hits it in a direction making an angle ${37}^{\circ }$ with car as seen from street. The bullet enters one edge of the car at the corner and passes out diagonally opposite corner. Time for bullet to cross car is (Write upto two digits after the decimal point.)

Answer 1

Let speed of bullet be V

$V\cos 37-13=\frac{2}{t}\dots \dots \left(1\right)$ and $V\sin 37=\frac{3}{t}\dots \dots \left(2\right)$

Solving (1) and (2)

We get $t=\frac{2}{13}$