A car A is going north-east at 80km/hr, and another car B is going south-east at 60km/hr. Then the direction of the velocity of A relative to B makes with the north an angle $α$ such that tance is -

\frac{1}{7}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

7

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{7}{5}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $7$
$V_{A} = \frac{80}{\sqrt{2}}^j + \frac{80}{\sqrt{2}}^i$
$V_{B} = \frac{60}{\sqrt{2}}^i + \frac{60}{\sqrt{2}}^j$
$V_{A B} = V_{A} - V_{B}$
$= \frac{140}{\sqrt{2}}^j + \frac{20}{\sqrt{2}}^i$
$θ =$ angle with
$= {tan}^{- 1} (\frac{140}{20})$
$= {tan}^{- 1} (7)$

Suggest Corrections

Similar questions

A car $A$ is going north-east at $80 k m / h$ and another car $B$ is going south-east at $60 k m / h$ . Then the direction of the velocity of $A$ relative to $B$ makes with the north an $α$ angle such that $tan α is$ :

Q. A car A is going north east at 80 kmh-1 and another car B is going south east with a velocity of

{60 k m h}^{- 1}

. the velocity of A relative to B makes an angle with the north equal to:

Q. A motorboat is racing towards north at

25 km/h

and the water current in that region is

10 km/h

in the direction of

60^{\circ}

east of south. The resultant velocity of the boat is

Q. In going from one city to another, a car travels

75 k m

north,

60 k m

north-west and

20 k m

east. The magnitude of displacement between the two cities is (take

\sqrt{2} = 0.7

)

A car has a velocity $\to v = 80 k m / h r$ towards east. Another car on the road has a velocity = $\to - v$ . The magnitude and direction of velocity of second car is

Join BYJU'S Learning Program

A car A is going north-east at 80km/hr, and another car B is going south-east at 60km/hr. Then the direction of the velocity of A relative to B makes with the north an angle α such that tance is -

The correct option is C 7VA=80√2^j+80√2^iVB=60√2^i+60√2^jVAB=VA−VB=140√2^j+20√2^iθ= angle with =tan−1(14020)=tan−1(7)

A car A is going north-east at 80km/hr, and another car B is going south-east at 60km/hr. Then the direction of the velocity of A relative to B makes with the north an angle $α$ such that tance is -

The correct option is C $7$
$V_{A} = \frac{80}{\sqrt{2}}^j + \frac{80}{\sqrt{2}}^i$
$V_{B} = \frac{60}{\sqrt{2}}^i + \frac{60}{\sqrt{2}}^j$
$V_{A B} = V_{A} - V_{B}$
$= \frac{140}{\sqrt{2}}^j + \frac{20}{\sqrt{2}}^i$
$θ =$ angle with
$= {tan}^{- 1} (\frac{140}{20})$
$= {tan}^{- 1} (7)$