You visited us 1 times! Enjoying our articles? Unlock Full Access!

Third Equation of Motion

A car A of ma...

Question

A car A of mass $1500 k g$ is travelling at $25 m s^{- 1}$ collides with another car B of mass $1000 k g$ travelling at $15 m s^{- 1}$ in the same direction. After collision, the velocity of car A reduces to $20 m s^{- 1}$ . Calculate the velocity of car B after the collision.

32.5 m s^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

35 m s^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

22.5 m s^{- 1}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

25 m s^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $22.5 m s^{- 1}$
Given, mass of car A, $m_{1} = 1500 k g$ ; initial velocity of car A, $u_{1} = 25 m s^{- 1}$ ; initial velocity of car B, $u_{2} = 15 m s^{- 1}$ ; mass of car B, $m_{2} = 1000 k g$ and final velocity of car A, $v_{1} = 20 m s^{- 1}$ .
Let final velocity of car B be $v_{2}$ .
According to law of conservation of momentum, we know
$m_{1} \times u_{1} + m_{2} \times u_{2} = m_{1} \times v_{1} + m_{2} \times v_{2}$
Substituting in the equation, we get ,
$1500 \times 25 + 1000 \times 15 = 1500 \times 20 + 1000 v_{2}$
$\Rightarrow$ $52500 = 30000 + 1000 v_{2}$
$\Rightarrow$ $22500 = 1000 v_{2}$
$\Rightarrow$ $v_{2} = 22.5 m s^{- 1}$

Suggest Corrections

Similar questions

A car of mass 1500 kg travelling at 25 m/s collides with another car B of mass 1000 kg travelling at 15 m/s in the same direction after the collision, the velocity of car B will be

Q. The car

A

of mass

1500 k g

travelling at

40 m / s

collides with another car

^{'} B^{'}

of mass

1250 k g

travelling at

25 m / s

in the same direction. After collision the velocity of car

^{'} A^{'}

becomes

30 m / s

. calculate the velocity of car

^{'} B^{'}

after the collision.

Q. A car A of mass

1500 kg

is travelling at

25 {m s}^{- 1}

collides with another car B of mass

1000 kg

travelling at

15 {m s}^{- 1}

in the same direction. After collision, the velocity of car A reduces to

20 {m s}^{- 1}

. Calculate the velocity of car B after the collision.

Ball A of mass $5 k g$ travelling at $6 m s^{- 1}$ collides with another ball B of mass $2 k g$ travelling at $2 m s^{- 1}$ in the same direction. After collision, the velocity of ball A reduces to $2 m s^{- 1}$ . Calculate the velocity of ball B after the collision.

Two cars A and B cross a point P with velocities 10/m and 15 m/s. After that, they move with different uniform accelerations and the car A overtakes B with a speed of 25 ms^-1. What is velocity of B at that instant?

Join BYJU'S Learning Program

A car A of mass 1500 kg is travelling at 25 ms−1 collides with another car B of mass 1000 kg travelling at 15 ms−1 in the same direction. After collision, the velocity of car A reduces to 20 ms−1. Calculate the velocity of car B after the collision.

A car A of mass $1500 k g$ is travelling at $25 m s^{- 1}$ collides with another car B of mass $1000 k g$ travelling at $15 m s^{- 1}$ in the same direction. After collision, the velocity of car A reduces to $20 m s^{- 1}$ . Calculate the velocity of car B after the collision.