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Standard VIII

Physics

Velocity

A car acceler...

Question

A car accelerates at $1.5 m / s^{2}$ on a straight road. How much is the increase in velocity in 4 s?

6 m/s

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4 m/s

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3 m/s

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1 m/s

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Solution

The correct option is A
6 m/s

From the first equation of motion, $v = u + a t$

$\Rightarrow v - u = a t = 1.5 \times 4 = 6 m / s$

So, the change in velocity is 6 m/s.

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A car accelerates at 1.5 m/s2 on a straight road. How much is the increase in velocity in 4 s?

The correct option is A 6 m/s From the first equation of motion, v=u+at ⇒v−u=at=1.5×4=6 m/s So, the change in velocity is 6 m/s.

A car accelerates at $1.5 m / s^{2}$ on a straight road. How much is the increase in velocity in 4 s?

The correct option is A
6 m/s

From the first equation of motion, $v = u + a t$

$\Rightarrow v - u = a t = 1.5 \times 4 = 6 m / s$

So, the change in velocity is 6 m/s.