A car accelerates from rest with $2 m / s^{2}$ on a straight line path and then comes to rest after applying brakes. Total distance travelled by the car is $100 m$ in $20$ seconds. Then the maximum velocity attained by the car is

10 m / s

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20 m / s

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15 m / s

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5 m / s

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Solution

The correct option is B $10 m / s$
Area under the v-t curve (in this case it is a triangle) is same as displacement.
$\frac{1}{2} v t = 100 \Rightarrow v = \frac{200}{t} = 10 m / s$

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A car accelerates from rest with 2m/s2 on a straight line path and then comes to rest after applying brakes. Total distance travelled by the car is 100 m in 20 seconds. Then the maximum velocity attained by the car is

The correct option is B 10m/sArea under the v-t curve (in this case it is a triangle) is same as displacement.12vt=100⇒v=200t=10 m/s

A car accelerates from rest with $2 m / s^{2}$ on a straight line path and then comes to rest after applying brakes. Total distance travelled by the car is $100 m$ in $20$ seconds. Then the maximum velocity attained by the car is

The correct option is B $10 m / s$
Area under the v-t curve (in this case it is a triangle) is same as displacement.
$\frac{1}{2} v t = 100 \Rightarrow v = \frac{200}{t} = 10 m / s$