A car accelerates uniformly from 13ms–1 to 31ms–1 while entering the motorway, covering a distance of 220m. Then the acceleration of the car will be:
A
2.9ms−2
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B
1.8ms−2
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C
4ms−2
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D
2.2ms−2
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Solution
The correct option is B1.8ms−2 Given, s=220m u=13ms−1 v=31ms−1 a=? Using 3rd equation of motion i.e. v2=u2+2as (31)2=(13)2+(2×a×220) 961=169+440a 440a=961−169=792 ∴a=792440=1.8ms−2