A car accelerates uniformly from 20ms–1 to 50ms–1 while entering the motorway, covering a distance of 200m. Then the acceleration of the car will be:
A
4.25ms−2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
6.30ms−2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
5.25ms−2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
5.65ms−2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C5.25ms−2 Given, s=200m u=20ms−1 v=50ms−1 a=? Using 3rd equation of motion i.e. v2=u2+2as (50)2=(20)2+(2×a×200) 2500=400+400a 400a=2500−400=2100 ∴a=2100400=5.25ms−2